Atoms and Molecules: 75 Question Answer

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In this post, questions and answers of atoms and molecules are provided which includes NCERT questions as well.

1. In a reaction 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass carbonate.

Answer:

atoms and molecules,

2. Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?

Answer: Ratio of H : O by mass in water (H2O) is:
∴ 1 : 8 = 3 : x
x = 8 x 3
x = 24 g
∴ 24 g of oxygen gas would be required to react completely with 3 g of hydrogen gas.

3. Which postulate of Dalton’s atomic theory is the result of the law of conservation of mass?

Answer: The postulate of Dalton’s atomic theory that is the result of the law of conservation of mass is—the relative number and kinds of atoms are constant in a given compound. Atoms cannot be created nor destroyed in a chemical reaction.

4. Which postulate of Dalton’s atomic theory can explain the law of definite proportions?

Answer: The relative number and kinds of atoms are constant in a given compound.

5. Define the atomic mass unit.

Answer: One atomic mass unit is equal to exactly one-twelfth (1/12th) the mass of one atom of carbon-12. The relative atomic masses of all elements have been found with respect to an atom of carbon-12.

6. Why is it not possible to see an atom with naked eyes?

Answer: Atom is too small to be seen with naked eyes. It is measured in nanometres.

1 m = 109 nm

7. Write down the chemical formulae of:
(i) Sodium oxide
(ii) Aluminium chloride
(iii) Sodium sulphide
(iv) Magnesium hydroxide

Learn to write chemical formula: https://youtu.be/9qbLgB-MtbU

Answer: The formulae are as:

Atoms and Molecules: 75 Question Answer

8. What is meant by the term chemical formula?

Answer: The chemical formula of the compound is a symbolic representation of its composition, e.g., chemical formula of sodium chloride is NaCl.

9. How many atoms are present in a:
(i) H2S molecule and
(ii) PO43- ion?

Answer: (i) In H2S, 3 atoms are present, i.e., 2 atoms of hydrogen and 1 atom of sulphur.
(ii) In PO43-, 5 atoms are present, i.e., 1 atom of phosphorous and 4 atoms of oxygen.

10. Calculate the molecular masses of H2, O2, Cl2, CO2, CH4, C2H2, NH3, CH3OH.

Answer: The molecular masses are as follows:

Atoms and Molecules: 75 Question Answer

11. Calculate the formula unit masses of ZnO, Na2O, K2CO3. Given atomic masses of Zn = 65 u, Na = 23 u, K = 39 u, C = 12 u, and O = 16 u.

Answer: The formula unit mass of
(i) ZnO = 65 u + 16 u = 81 u
(ii) Na2O = (23 u x 2) + 16 u = 46 u + 16 u = 62 u
(iii) K2CO3 = (39 u x 2) + 12 u + 16 u x 3 = 78 u + 12 u + 48 u = 138 u

12. If one mole of carbon atoms weigh 12 grams, what is the mass (in grams) of 1 atom of carbon?

Answer:

Atoms and Molecules: 75 Question Answer

13. Which has more number of atoms, 100 grams of sodium or 100 grams of iron (given atomic mass of Na = 23 u, Fe = 56 u)?

Answer:

Atoms and Molecules: 75 Question Answer

14. A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

Answer: Compound of boron and oxygen contains boron and oxygen only.

Total mass of sample (boron + oxygen) = 0.24 g

Mass of boron = 0.096 g

Mass of oxygen = 0.144 g

Percentage composition of boron = (Mass of boron/Mass of sample) x 100= (0.096/0.24) x 100 = 0.4 x 100 = 40%

Percentage composition of oxygen = 100 – Percentage composition of boron = 100 – 40 = 60%

15. When 3.0 g of carbon is burnt in 8.00 g oxygen, 11.00 g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00 g of carbon is burnt in 50.00 g of oxygen? Which law of chemical combination will govern your answer?

Answer: The reaction of burning of carbon in oxygen may be written as:

Atoms and Molecules: 75 Question Answer

The reaction clearly shows that 12 g of carbon burns in 32 g oxygen to form 44 g of carbon dioxide.

Therefore 3 g of carbon reacts with 8 g of oxygen to form 11 g of carbon dioxide. It is given that 3.0 g of carbon is burnt with 8 g of oxygen to produce 11.0 g of CO2.

Consequently 11.0 g of carbon dioxide will be formed when 3.0 g of C is burnt in 50 g of oxygen consuming only 8 g of oxygen, leaving behind (50 – 8) g = 42 g of O2.

This answer governs the law of constant proportion.

16. What are polyatomic ions? Give examples.

Answer: The ions which contain more than one atoms (same kind or may be of different kind) and behave as a single unit are called polyatomic ions e.g., OH, SO42-, CO32-.

17. Write the chemical formulae of the following compounds:
(a) Magnesium chloride
(b) Calcium oxide
(c) Copper nitrate
(d) Aluminium chloride
(e) Calcium carbonate

Answer: (a) Magnesium chloride
Symbol Mg Cl
Change +2 -1
Formula MgCl2

(b) Calcium oxide
Symbol Ca O
Charge +2 -2
Formula

CaO

(c) Copper nitrate
Symbol Cu NO3
Charge +2 -1
Formula Cu(NO3)2

(d) Aluminium chloride
Symbol Al Cl
Change +3 -1
Formula AlCl3

(e) Calcium carbonate
Symbol Ca CO3
Change +2 -2
Formula CaCO3

18. Give the names of the elements present in the following compounds:
(a) Quick lime
(b) Hydrogen bromide
(c) Baking powder
(d) Potassium sulphate

Answer: (a) Quick lime Calcium oxide (CaO)
Elements Calcium and oxygen
(b) Hydrogen bromide (HBr)
Elements Hydrogen and bromine
(c) Baking powder Sodium hydrogen carbonate (NaHCO3)
Elements Sodium, hydrogen, carbon and oxygen
(d) Potassium sulphate K2SO4
Elements Potassium, sulphur and oxygen

19. Calculate the molar mass of the following substances:
(a) Ethyne, C2H2
(b) Sulphur molecule, S8
(c) Phosphorus molecule, P4 (Atomic mass of phosphorus = 31)
(d) Hydrochloric acid, HCl
(e) Nitric acid, HNO3

Answer: The molar mass of the following is: [Unit is ‘g/mol’]
(a) Ethyne, C2H2 = 2 x 12 + 2 x 1 = 24 + 2 = 26 g/mol
(b) Sulphur molecule, S8 = 8 x 32 = 256 g/mol
(c) Phosphorus molecule, P4=4 x 31 = 124 g/mol
(d) Hydrochloric acid, HCl = 1 x 1 + 1 x 35.5 = 1 + 35.5 = 36.5 g/mol
(e) Nitric acid, HNO3 = 1 x 1 + 1 x 14 + 3 x 16 = 1 + 14 + 48 = 63 g/mol

20. What is the mass of:
(a) 1 mole of nitrogen atoms?
(b) 4 moles of aluminium atoms (Atomic mass of aluminium = 27)?
(c) 10 moles of sodium sulphite (Na2SO3)?

Answer: (a) Mass of 1 mole of nitrogen atoms = 14 g
(b) 4 moles of aluminium atoms
Mass of 1 mole of aluminium atoms = 27 g
∴ Mass of 4 moles of aluminium atoms = 27 x 4 = 108 g
(c) 10 moles of sodium sulphite (Na2SO3)
Mass of 1 mole of Na2SO3 = 2 x 23 + 32 + 3 x 16 = 46 + 32 + 48 = 126 g
∴ Mass of 10 moles of Na2SO3 = 126 x 10 = 1260 g

21. Convert into mole:
(a) 12 g of oxygen gas
(b) 20 g of water
(c) 22 g of Carbon dioxide

Answer: (a) Given mass of oxygen gas = 12 g
Molar mass of oxygen gas (O2) = 32 g
Mole of oxygen gas 12/32 = 0.375 mole
(b) Given mass of water = 20 g
Molar mass of water (H2O) = (2 x 1) + 16 = 18 g
Mole of water = 20/18 = 1.12 mole
(c) Given mass of Carbon dioxide = 22 g
Molar mass of carbon dioxide (CO2) = (1 x 12) + (2 x 16)
= 12 + 32 = 44 g
∴ Mole of carbon dioxide = 22/44 = 0.5 mole

22. What is the mass of:
(a) 0.2 mole of oxygen atoms?
(b) 0.5 mole of water molecules?

Answer: (a) Mole of oxygen atoms = 0.2 mole
Molar mass of oxygen atoms = 16 g
Mass of oxygen atoms = 16 x 0.2 = 3.2 g
(b) Mole of water molecule = 0.5 mole
Molar mass of water molecules = (2 x 1) + 16= 18 g
Mass of H2O = 18 x 0.5 = 9 g

23. Calculate the number of molecules of sulphur (S8) present in 16 g of solid sulphur.

Answer: 1 mole of S8 = Molar mass of S8 = 256 g = 6.022 x 1023 molecule
Given mass of sulphur = 16 g

Atoms and Molecules: 75 Question Answer

24. Calculate the number of aluminium ions present in 0.051 g of aluminium oxide. (Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of Al = 27 u)

Answer: Molar mass of aluminium oxide Al2O3
= (2 x 27) + (3 x 16)
= 54 + 48 = 102 g.

Atoms and Molecules: 75 Question Answer

25. The atomicity of K2Cr2O7 is: (a) 9 (b) 11 (c) 10 (d) 12

Answer: (b) 11 as the molecule contains total 11 atoms.

26. The formula for quick lime is: (a) CaCl2 (b) CaCO3 (c) Ca(OH)2 (d) CaO

Answer: (d) CaO

27. The symbol of cadmium is: (a) Ca (b) Cu (c) Cm (d) Cd

Answer: (d) Cd is the symbol

28. All noble gas molecules are: (a) monoatomic (b) diatomic (c) triatomic (d) tetratomic

Answer: (a) monoatomic, e.g., He, Ne, Ar, Kr.

29. The valency of nitrogen in NH3 is: (a) 1 (b) 3 (c) 4 (d) 5

Answer: (b) 3

30. The formula of ethanol is C2H5—OH. Its molecular mass is: (a) 46 u (b) 34 u (c) 34 g (d) 46 g

Answer: (a) 46 u

31. How many moles are present in 28 g of nitrogen atoms? (a) 1 mole (b) 2.3 moles (c) 0.5 mole (d) 2 moles

Answer: (d) 2 moles

32. The molecular mass of X is 106 u. X among the following is: (a) CaCO3 (b) SO3 (c) Na2CO3 (d) NaCl

Answer: (c) Na2CO3

33. Which among the following is not a postulate of Dalton’s atomic theory?
(a) Atoms cannot be created or destroyed.
(b) Atoms of different elements have different sizes, masses and chemical properties.
(c) Atoms of same elements can combine in only one ratio to produce more than one compound.
(d) Atoms are very tiny particles which cannot be divided further.

Answer: (c) Atoms of same elements can combine in only one ratio to produce more than one compound.

Correct postulate is: Atoms of same elements can combine in more than one ratio to produce more than one compound.

34. Pick up the wrong pairs/combination
(a) 6.022 x 1023 molecules of oxygen = 32 g of oxygen
(b) 6.022 x 1023 ions of sodium = 23 g of Na
(c) 6.022 x 1023 atoms of C = 24 g of carbon
(d) 6.022 x 1023 atoms of H = 1 g of H atoms

Answer: (c)

35. Define law of conservation of mass.

Answer: In a chemical reaction mass can neither be created nor destroyed.
e.g., 2Na + Cl2 → 2NaCl
2×23 + 2×35.5 → 2(23+35.5)

i.e., the total mass of the reactants is always equal to the total mass of the products.

36. Explain law of constant proportion.

Answer: In a chemical substance the elements are always present in definite proportions by mass.
e.g., In water, the ratio of the mass of hydrogen to the mass of oxygen H : O is always 1:8.

37. Who coined the term atom?

Answer: John Dalton coined the term atom.

38. Define atom.

Answer: The smallest particle of matter, which can take part in a chemical reaction is called atom.

39. Define molecule.

Answer: The smallest particle of an element or compound which can exist independently is called molecule.

40. Define atomicity.

Answer: The number of atoms constituting a molecule is known as its atomicity, e.g. H2S has 3 atoms, so its atomicity is 3.

41. What is atomic mass unit?

Answer: The sum of the atomic masses of all the atoms in a molecule of the substance is expressed.in atomic mass unit,

e.g., H2O = 1 x 2 + 16 = 18 u.

42. How do atoms exist?
Answer: Atoms exist in the form of atom, molecule or ions.

43. Give the atomicity of phosphorous and nitrogen.

Answer. The atomicity of phosphorus is P4 i.e., 4.
The atomicity of nitrogen is N2 i.e., 2.

44. What is an ion?

Answer: Charged atom is called as an ion. The ion can be positively charged called cation or negatively charged called anion.

45. Give one example of cation and anion.

Answer: Cation → Na+
Anion → Cl

46. Give one difference between cation and anion.

Answer: Cations are positively charged ion.
Anions are negatively charged ion.

47. Give the chemical formula for ammonium sulphate.

Answer: Ammonium sulphate
NH4+ SO42-
Chemical formula is (NH4)2SO4

48. What is Avogadro’s constant?

Answer: The Avogadro’s constant (6.022 x 1023) is defined as the number of atoms that are present in exactly 12 g of carbon-12.

49. Find the molecular mass of H2O.

Answer: Molecular mass of H2O = (2 x 1) + (16) = 2 + 16 = 18 u

50. Give the unit to measure size of atom and give size of hydrogen atom.

Answer: The unit to measure size of atom, is nanometer, size of hydrogen atom is 10-10m.

51. What is IUPAC, give its one function?

Answer: IUPAC is International Union for Pure and Applied Chemistry. It approves the names of elements.

52. Give the Latin name for sodium, potassium, gold and mercury.

Answer: Sodium: Natrium, Gold: Aurum, Potassium: Kalium, Mercury: Hydrargyrum.

53. What is the ratio by mass of combining elements in H2O, CO2 and NH3?

Answer: H2O ratio by mass of combining elements 2 : 16 =1 : 8 (H : O)
CO2 ratio by mass of combining elements 12 : 32 = 3 : 8 (C : O)
NH3 ratio by mass of combining elements 14 : 3 =14 : 3 (N : H)

54. Define valency and give the valency for the following elements: Magnesium, Aluminium, Chlorine and Copper.

Answer: The combining capacity of an element is called its valency. Valency of the following elements:
Magnesium – 2
Aluminium – 3
Chlorine – 1
Copper – 2

55. What is polyatomic ton? Give one example.

Answer: A group of atoms carrying a charge is known as a polyatomic ion.
e.g., Ammonium – NH4+ Nitrate – NO3

56. Write down the chemical formula for: Copper nitrate, calcium sulphate and aluminium hydroxide.

Answer: Chemical formula:
Copper nitrate: Cu(NO3)

Calcium sulphate: CaSO4 

Aluminium hydroxide: Al(OH)3

57. What is formula unit mass? How is it different from molecular mass?

Answer: The formula unit mass of a substance is a sum of the atomic masses of all atoms in a formula unit of a compound. The constituent particles of formula unit mass are ions and the constituent particles of molecular mass are atoms.

58. Find the number of moles in the following:
(i) 50 g of H2O
(ii) 7 g of Na

Answer: (i) Molar mass of H2O = 18 g/mol

Given mass of H2O = 50 g

Number of moles in 50 g of H2O = Given mass/Molar mass = 50/18 = 2.78 mol

(ii) Molar mass of Na = 23 g/mol

Given mass of Na = 7 g

Number of moles in 7 g of Na = Given mass/Molar mass = 7/23 = 0.304 mol

59. Find the number of atoms in the following:
(i) 0.5 mole of C atom
(ii) 2 mole of N atom

Answer: (i) 0.5 mole of C atom:
Number of atoms in 1 mole of C atom = 6.022 x 1023 atoms
Number of atoms in 0.5 mole of C atom = 6.022 x 1023 x 0.5 = 3.011 x 1023 atoms
(ii) 2 mole of N atom:
Number of atoms in 1 mole of N atom = 6.022 x 1023 atoms
Number of atoms in 2 mole of N atom = 6.022 x 2 x 1023 = 1.2044 x 1024 atoms

60. Find the mass of the following:
(i) 6.022 x 1023 number of O2 molecules
(ii) 1.5 mole of CO2 molecule

Answer: (i) 6.022 x 1023 number of O2 molecules:
Mass of 1 mole of Omolecule = 6.022 x 1023 molecules = 32 g
(ii) 1.5 mole of CO2 molecule:
Mass of 1 mole of CO2 molecule = 6.022 x 1023 molecules = 44 g
Mass of 1.5 mole CO2 molecule = 44 x 1.5 = 66 g

61. Show the relationship between mole, Avogadro number and mass.

Answer:

Atoms and Molecules: 75 Question Answer
Atoms and Molecules: 75 Question Answer

62. What are the rules for writing the symbol of an element?

Answer: IUPAC (International Union of Pure and Applied Chemistry) approves name of elements.
Symbols are the first one or two letters of the element’s name in English. The first letter of a symbol is always written as a capital letter (upper case) and the second letter as a small letter (lower case).
e.g., Hydrogen: H and Helium: He
Some symbols are taken from the names of elements in Latin, German or Greek.
e.g., Symbol of iron is Fe, its Latin name is Ferrum.
Symbol of sodium is Na, its Latin name is Natrium.

63. Explain relative atomic mass and relative molecular mass.

Answer: Relative atomic mass: It can be defined as the number of times one atom of given element is heavier than 1/12th of the mass of an atom of carbon-12. Relative Molecular Mass: It is defined as the number of times one molecule
of a substance or given element is heavier than 1/12th of the mass of one atom of carbon-12.

64. The formula of carbon-dioxide is CO2. What information do you get from this formula?

Answer: (i) CO2 represents carbon-dioxide.
(ii) CO2 is one molecule of carbon-dioxide.
(iii) CO2 is one mole of carbon-dioxide i.e., it contains 6.022 x 1023 molecules of carbon dioxide.
(iv) CO2 contains 1 atom of carbon and two atoms of oxygen.
(v) CO2 represents 44 g of molar mass.

65. State 3 points of difference between an atom and an ion.

Answer:

Atoms and Molecules: 75 Question Answer

66. Calculate the formula unit mass of NaCl and CaCl2. (Atomic mass: Na = 23, Cl = 35.5, Ca = 40)

Answer: Formula unit mass of NaCl = 23 + 35.5 = 58.5 u
Formula unit mass of CaCl2 = 40 + (2 x 35.5) = 40 + 71 = 111 u

67. The ratio by mass for hydrogen and oxygen in water is given as 1 : 8 respectively. Calculate the ratio by number of atoms for a water molecule.

Answer: The ratio by number of atoms for a water molecule are:

Atoms and Molecules: 75 Question Answer

Thus, the ratio by number of atoms for water is H : O = 2 : 1.

68. Write down the chemical formula for the following compounds:
(a) Aluminium carbonate
(b) Calcium sulphide
(c) Zinc carbonate
(d) Copper phosphate
(e) Magnesium bicarbonate
(f) Aluminium hydroxide

Learn to write chemical formula: https://youtu.be/9qbLgB-MtbU

Answer: The chemical formula are:

Atoms and Molecules: 75 Question Answer
Atoms and Molecules: 75 Question Answer

69. Give the atomicity of the following compounds:
(a) Ca(OH)2 (b) Mg(HCO3)2 (c) Cu2O (d) H2SO4 (e) Al2(SO4)3 (f) MgCl2

Answer: Count the total number of atoms to find the atomicity of the given molecules. The atomicity of the molecules are as:

Atoms and Molecules: 75 Question Answer

70. Explain the difference between 2O, O2 and O3.

Answer: 2O: It represents 2 atoms of oxygen, cannot exist independently.
O2: It represents one molecule of oxygen (made up of 2 atom), can exist freely.
O3: It represents one molecule of ozone (made up of 3 atoms), can exist independently.

71. (a) How do atoms exist?
(b) What is atomicity?
(c) What are polyatomic ions?

Answer: (a) Atoms of some elements are not able to exist independently. For such elements atoms form molecules and ions. In case of metals and inert gases atoms can exist independently.

Metals: Na, Mg, Al, K, Li, etc.

Inert gases: He, Ne, Ar, Kr, Xe, Rn

Non metals: H2, Cl2, F2, O2, P4, S8, etc (Exceptional non-metal is carbon exists as C)

(b) The number of atoms constituting a molecule is known as its atomicity.
E.g.,O3: Atomicity is 3
O2: Atomicity is 2

(c) Polyatomic ions: When more than two atoms combine together and act like an atom with a charge on it is called polyatomic ion. e.g., OH, NO3, NH4+

72. Calculate:
(a) the mass of one atom of oxygen
(b) the mass of one molecule of oxygen
(c) the mass of one mole of oxygen gas
(d) the mass of one ion of oxygen
(e) the number of atoms in 1 mole of oxygen molecule

Answer:

Atoms and Molecules: 75 Question Answer
Atoms and Molecules: 75 Question Answer

73. What is meant by atomic mass, gram atomic mass of an element? Why is the mass have different expressions i.e., ‘u’ and ‘g’?

Answer: The atoms are very tiny and their individual mass cannot be calculated as it is negligible. Hence, the mass of atoms is expressed in units with respect to a fixed standard.

Initially, hydrogen atom with mass 1 was taken as standard unit by Dalton. Later, it was replaced by oxygen atom (O =16). But due to the isotopes the masses were found in fractions instead of whole number. Hence, carbon (C=12) isotope was taken as standard unit and was universally accepted.
The atomic mass unit is equal to one twelfth (1/12) the mass of an atom of carbon-12, its unit is u.
Gram atomic mass: When the atomic mass of an element is expressed in grams, it is called the gram atomic mass of the element.
The mass of atoms, molecules is expressed in ‘u’ and the mass of moles i.e., molar mass is expressed in g.

74. Define a mole. Give the significance of the mole.

Answer: Mole-One mole of any species (atoms, molecules, ions or particles) is that quantity or number having a mass equal to its atomic or molecular mass in grams.
1 mole = 6.022 x 1023 in number (atoms, molecules, ions or particles)

Significance of the mole:

1. A mole gives the number of entities present i.e, 6.022 x 1023 particles of the substance.

2. Mass of 1 mole is expressed as M grams.

3. Mass of 1 mole = 6.022 x 1023 particles

75. A customer buys a gold jewellery, he is told that the jewellery has 90% gold and the rest copper. He is given a bill which amounts 100% charges of gold. The customer refuses to pay the bill for 100% gold but brings it to 90% gold amount and settles the bill.
(a) How many atoms of gold are present in 1 gram of gold?
(b) What is the ratio of gold and copper in the jewellery?
(c) What value of customer is reflected in the above statement?

Answer:

Atoms and Molecules: 75 Question Answer

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