It is a question based on stoichiometric calculation.
How many moles of UF6 would have to be decomposed to provide enough fluorine to prepare 1.25 mol of CF4 ? (Assume sufficient carbon is available)
UF6→ U + 3F2 ……….. (1)
C + 2F2→ CF4 ……….. (2)
From reaction (2),
1 mole CF4 is prepared from 2 mole F2
Then, 1.25 mole CF4 will be prepared from F2 = (2 mol/1 mol)*(1.25 mol) = 2.5 mol
Hence, from reaction (2) it is clear that 2.5 mole F2 is required to produce 1.25 mole CF4
From reaction (1)
3 mole F2 is produced from 1 mole UF6
Then, 2.5 mole F2 will be produce from UF6 = (1 mol/3 mol)*(2.5 mol) = 0.83 mol
Hence, 0.83 mole UF6 would have to be decomposed to provide enough fluorine to prepare 1.25 mole CF4.