E° for copper electrode is +0.34 V, how will you calculate its emf value?

Question: If E° for copper electrode is +0.34 V, how will you calculate its emf value when the solution in contact with it is 0.1 M in copper ions? How does emf for copper electrode change when concentration of Cu²⁺ ions in the solution is decreased?

Solution: The emf of an electrode when dipped in different concentrated solution is given by by the Nernst equation:

n is the number of electrons involved in the equation, i.e., 2

Cu²⁺ + 2e^– → Cu

Substituting the given values in the Nernst equation, we get

When concentration of Cu2+ ion in solution decreases the emf of the electrode decreases.

In that case, it has decreased from 0.34 V to 0.3105 V.

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