Calculate the number of sulphate ions in 100 ml of 0.001 M H2SO4 solution.

Chirag Gupta

3 years ago

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We are given with,

Molarity = 0.001 M

Volume = 100 ml = 0.1 L

Number of moles of H₂SO₄ = Molarity*Volume = 0.001 M*0.1 L = 0.0001 mole

Dissociation of sulphuric acid occurs as: H₂SO₄ ⟶ 2H⁺ + SO₄^2-

From the above equation, 1 molecule H₂SO₄ given 1 SO₄^2- ion

then, 1 mole of H₂SO₄ contain 1 mole SO₄^2- ion

So, 0.0001 mole H₂SO₄ contain 0.0001 mole of SO₄^2- ion

Number of sulphate ions in 0.0001 mole H₂SO₄ = Moles of SO₄^2-ions*Avogadro’s number

= 0.0001*6.022*10²³ = 6.022*10¹⁹ ions

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