Calculate the number of sulphate ions in 100 ml of 0.001 M H2SO4 solution.

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We are given with,
 
Molarity = 0.001 M
 
Volume = 100 ml = 0.1 L
 
Number of moles of H2SO4 =  Molarity*Volume = 0.001 M*0.1 L = 0.0001 mole
 
Dissociation of sulphuric acid occurs as: H2SO4 ⟶ 2H+ + SO42-
 
From the above equation, 1 molecule H2SO4 given 1 SO42- ion
 
then, 1 mole of H2SO4 contain 1 mole SO42- ion
 
So, 0.0001 mole H2SO4 contain 0.0001 mole of SO42- ion
 
Number of sulphate ions in 0.0001 mole H2SO4 = Moles of SO42- ions*Avogadro’s number
= 0.0001*6.022*1023 = 6.022*1019 ions
 

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