We are given with,
Molarity = 0.001 M
Volume = 100 ml = 0.1 L
Number of moles of H2SO4 = Molarity*Volume = 0.001 M*0.1 L = 0.0001 mole
Dissociation of sulphuric acid occurs as: H2SO4 ⟶ 2H+ + SO42-
From the above equation, 1 molecule H2SO4 given 1 SO42- ion
then, 1 mole of H2SO4 contain 1 mole SO42- ion
So, 0.0001 mole H2SO4 contain 0.0001 mole of SO42- ion
Number of sulphate ions in 0.0001 mole H2SO4 = Moles of SO42- ions*Avogadro’s number
= 0.0001*6.022*1023 = 6.022*1019 ions