Last Updated on May 4, 2023 by Chirag Gupta What makes the matter to exist in any one of three state of matter? Why should the properties of solids, liquids and gases be different? Before finding a solution for the above mentioned questions, let us recollect that: All matter is made up of very small […]
What factors governs the state of matter? Read More »
Last Updated on May 11, 2022 by Chirag Gupta We are given with, Molarity = 0.001 M Volume = 100 ml = 0.1 L Number of moles of H2SO4 = Molarity*Volume = 0.001 M*0.1 L = 0.0001 mole Dissociation of sulphuric acid occurs as: H2SO4 ⟶ 2H+ + SO42- From the
Calculate the number of sulphate ions in 100 ml of 0.001 M H2SO4 solution. Read More »
Last Updated on September 24, 2022 by Chirag Gupta Given mass of CO2 = 200 mg = 0.2 g Molar mass of CO2 = 44 g/mol Number of moles of 200 mg CO2 = Given mass/Molar mass of CO2 = 0.2 g/44 g mol-1 = 0.00454 mole Number of molecules of CO2 removed = 1021
From 200 mg of CO2, 10^21 molecules are removed. How many moles of CO2 are left? Read More »
Last Updated on May 11, 2022 by Chirag Gupta Q. Assertion : The element having with electronic configuration 1s2 2s2 2p6 3s2 and 1s2 2s2 belong to the same group Reason: Both have same number of electrons in the valence shell Solution: Elements having same number of valence shell are present in same
Assertion-Reason based electronic configuration Read More »
Last Updated on May 11, 2022 by Chirag Gupta 30% w/v H2SO4 means 30 g H2SO4 in 100 ml solution. Mass of H2SO4 = 30 g Density of H2SO4 = 1.05 g/ml Volume of H2SO4 = Mass/Density = (30 g)/(1.05g/ml) = 28.57 ml Volume of solution = 100 ml Density of solution = 1.5 g/ml Mass of
Last Updated on October 27, 2022 by Chirag Gupta In KMnO4, oxidation state of Mn is +7. As the oxidation state of atom increases, the element become more electronegative in nature. Mn gain 5 electron in acidic medium and reduces to +2 oxidation state. Gain of 5 electron shows that the electronegativity of Mn
Why KMnO4 act as a good oxidizing agent in acidic medium? Read More »
Last Updated on October 27, 2022 by Chirag Gupta Question: If E° for copper electrode is +0.34 V, how will you calculate its emf value when the solution in contact with it is 0.1 M in copper ions? How does emf for copper electrode change when concentration of Cu2+ ions in the solution is decreased?
E° for copper electrode is +0.34 V, how will you calculate its emf value? Read More »
Last Updated on September 24, 2022 by Chirag Gupta Molar conductivity increases with increase in volume and when volume increases the concentration of solution decreases (because no.of ions in the solution decrease) which makes the solution dilute. On dilution when concentration approaches zero, the molar conductivity is known as limiting molar conductivity. In
How can you determine limiting molar conductivity for strong and weak electrolyte? Read More »
Last Updated on September 24, 2022 by Chirag Gupta Solution: Given, [A]=0.1 mol L-1, [B]=0.2 mol L-1, k = 2.0×10-6 mol-2 L2 s-1Rate =k[A][B]2 = (2.0x 10-6 ) x (0.1 mol L-1) x (0.2 mol L-1) 2 = 8.0 x 10-9 mol-2 L2 s-1. The concentration of A is reduced to (0.1 – 0.06) = 0.04 mol L-1.Now according to the equation 1 mole of
Calculate the initial rate of reaction. Read More »
Last Updated on September 24, 2022 by Chirag Gupta Let x g of each gas is mixed. Molar mass of ethane = 30 g/mol Molar mass of hydrogen = 2 g/mol Mole = Given mass/Molar mass Moles of ethane = (x/30) mol Moles of hydrogen = (x/2) mol
